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# How do you write 625 as a product of prime factors?

## How do you write 625 as a product of prime factors?

625 can be expressed as, 625 = 5 × 5 × 5 × 5. Therefore, the distinct prime factor is 5.

### How do you express 135 as a product of prime factors?

The prime factorization of 135 is 3 × 3 × 3 × 5.

What is the greatest prime factor of 625?

The prime factorization of 625 is 5 x 5 x 5 x 5 = 54.

What is 80 as a product of prime factors?

“When you will get the factors of 80 you will get 2 * 2 * 2 * 2 * 5. These numbers are the prime numbers that make them the prime factor of the 80.

## Why one is not a prime number?

Definition: A prime number is a whole number with exactly two integral divisors, 1 and itself. The number 1 is not a prime, since it has only one divisor.

### What is 180 as a product of prime factors?

The prime factorization of 180 is 5 × 2 × 2 × 3 × 3.

How to find the prime factors of 625?

Finding the prime factors of 625. To find the prime factors, you start by dividing the number by the first prime number, which is 2. If there is not a remainder, meaning you can divide evenly, then 2 is a factor of the number. Continue dividing by 2 until you cannot divide evenly anymore.

How to express a number as the product of its prime factors?

How to express a number as the product of its prime factors : Step 1 : Put the given number inside the “L” shape. Step 2 : We have to split the given number by prime numbers only. That is, always we have to put prime numbers out side the “L” shape. Step 3 : The tricks given below will be helpful to

## How to express 256 as the product of its prime factors?

Express 256 as the product of prime factors. Solution : Prime factors of 256 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 = 2 8

### How to find prime factorization by Trial Division?

Prime Factorization by Trial Division. Say you want to find the prime factors of 100 using trial division. Start by testing each integer to see if and how often it divides 100 and the subsequent quotients evenly. The resulting set of factors will be prime since, for example, when 2 is exhausted all multiples of 2 are also exhausted.